awips2/cave/com.raytheon.uf.viz.derivparam.python/localization/derivedParameters/functions/Laplacian.py
root e2ecdcfe33 Initial revision of AWIPS2 11.9.0-7p5
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Python

##
# This software was developed and / or modified by Raytheon Company,
# pursuant to Contract DG133W-05-CQ-1067 with the US Government.
#
# U.S. EXPORT CONTROLLED TECHNICAL DATA
# This software product contains export-restricted data whose
# export/transfer/disclosure is restricted by U.S. law. Dissemination
# to non-U.S. persons whether in the United States or abroad requires
# an export license or other authorization.
#
# Contractor Name: Raytheon Company
# Contractor Address: 6825 Pine Street, Suite 340
# Mail Stop B8
# Omaha, NE 68106
# 402.291.0100
#
# See the AWIPS II Master Rights File ("Master Rights File.pdf") for
# further licensing information.
###
## @file Laplacian.py
from numpy import empty
from numpy import shape
from numpy import NaN
##
# Function to calculate the Laplacian of qan.
#
# @param qan: The quantity array. This must be at rank 2, with at least 3
# cells in the first two dimensions.
# @param dx: The spacing between data points in the X direction.
# @param dy: The spacing between data points in the Y direction.
def execute(qan, dx, dy):
result = empty(shape(qan), dtype=qan.dtype)
# outer edges can't be calculated: fill with "invalid" value
result[0,:] = NaN
result[-1,:] = NaN
result[1:-1,0] = NaN
result[1:-1,-1] = NaN
# If dx and dy are matrices, we never use the outer edge,
# so strip it off so we don't have to use slice notation in the math.
# If they're actually scalars or 1-element matrices, we can't
# slice them so don't try.
shapedx = shape(dx)
if len(shapedx) < sum(shapedx):
dx = dx[1:-1,1:-1]
shapedy = shape(dy)
if len(shapedy) < sum(shapedy):
dy = dy[1:-1, 1:-1]
# Calculate the Q[i,j] + Q[i,j] array.
twoq = qan[1:-1,1:-1] * 2
# Calculate the X part of the answer
ans = qan[1:-1,0:-2] + qan[1:-1,2:]
ans -= twoq
ans /= dx * dx
# Calculate the Y part of the answer
term = qan[0:-2,1:-1] + qan[2:,1:-1]
term -= twoq
term /= dy * dy
# Combine pieces of the answer
ans += term
# fill middle block of result with ans
result[1:-1,1:-1] = ans
return result